Interview 150

Palindrome Number

Problem
LC 9
File
interview150_LC9PalindromeNumber.java
Path
pkg5leetcode/interview150/interview150_LC9PalindromeNumber.java
Package
pkg5leetcode.interview150
Command
java pkg5leetcode/interview150/interview150_LC9PalindromeNumber.java
Approach
Reverse half of digits; compare with remaining half.
Complexity
Time O(log n), Space O(1)

LeetCode solutions

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pkg5leetcode/interview150/interview150_LC9PalindromeNumber.java
1package pkg5leetcode.interview150;2 3/*4 * Palindrome Number | LC 95 * APPROACH: Reverse half of digits; compare with remaining half.6 * COMPLEXITY: Time O(log n), Space O(1)7 */8public class interview150_LC9PalindromeNumber {9    static boolean isPalindrome(int x) {10        if (x < 0 || (x % 10 == 0 && x != 0)) return false;11        int rev = 0;12        while (x > rev) {13            rev = rev * 10 + x % 10;14            x /= 10;15        }16        return x == rev || x == rev / 10;17    }18 19    public static void main(String[] args) {20        check(isPalindrome(121), "case1");21        check(!isPalindrome(-121), "case2");22        check(!isPalindrome(10), "case3");23        System.out.println("all tests passed");24    }25 26    static void check(boolean cond, String name) {27        if (!cond) throw new AssertionError("FAILED: " + name);28        System.out.println("  PASS " + name);29    }30}